the volume of a circular iron rod of length 5 cm is 3850 cm cube find its diameter
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for a cylindrical rod
length (l)=5. (given)
radius,r. =?
volume=3850cubic cm
volume of cylinder =π×r×r×h
3850 =22/7×r×r×5
3850/22 =1/7×r×r×5
( 175/5)×7. =r×r
7×7×5 =r×r
7√5 cm =r.
Hence ,radius of cylindrical iron rod is 7√5cm or 15.61 cm
length (l)=5. (given)
radius,r. =?
volume=3850cubic cm
volume of cylinder =π×r×r×h
3850 =22/7×r×r×5
3850/22 =1/7×r×r×5
( 175/5)×7. =r×r
7×7×5 =r×r
7√5 cm =r.
Hence ,radius of cylindrical iron rod is 7√5cm or 15.61 cm
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