Question

the volume of a circular pipe of length 50 cm is 1925cm^3. its diameter is??
First ans will get brainlist

Answer 1

Given:-

• length/height of circular pipe = 50cm
• volume of circular pipe = 1925cm³

Solution :-

Circular pipe is in the cylinder shape.

So,

Volume of cylinder = πr²h

1925cm³ = 22/7 × r² × 50cm

1925cm³ = 1100/7 × r²

r² = 1925 × 7/1100

r² = 13475/1100

r² = 12.25cm

r = √12.25cm

r = 3.5

Therefore, radius of cylinder is 12.25cm.

Now,

Diameter = 2r

= 2×3.5

= 7cm

Hence, diameter of cylinder is 7cm.

Answer 2

$\large\underline\blue{\bold{Given \:  Question :-  }}$

• The volume of a circular pipe of length 50 cm is 1925cm^3. its diameter is?

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$\huge \orange{AηsωeR} ✍$

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$\begin{gathered}\begin{gathered}\bf Given - \begin{cases} &\sf{Volume \: of \: pipe \: = 1925 \: {cm}^{3} } \\ &\sf{Length, \: of \: pipe \: = 50 \: cm} \end{cases}\end{gathered}\end{gathered}$

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$\begin{gathered}\begin{gathered}\bf To \: Find - \begin{cases} &\sf{diameter \: of \: pipe} \end{cases}\end{gathered}\end{gathered}$

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${ \boxed {\sf{Formula \: used :- }}}$

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${{ \boxed{\large{\bold\red{Volume_{(Cylinder)}\: = \:\pi r^2 h }}}}}$

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$\large\underline\purple{\bold{Solution :- }}$

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$\begin{gathered}\bf\red{According \: to \: statement \: - }\end{gathered}$

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☆ Volume of pipe, V = 1925 cm³

☆ Length, h of pioe = 50 cm.

☆ Let radius of pipe be 'r' cm.

Then, using formula,

${{ {\large{\bold\red{V\: = \:\pi r^2 h }}}}}$

☆ On substituting the values of V and h, we get,

$\sf \:  ⟼1925 \: = \dfrac{22}{7} \times {r}^{2} \times 50$

$\sf \:  ⟼ {r}^{2} = \dfrac{ 175 \: \: \cancel{1925} \times 7}{ 2 \: \: \cancel{22} \times 50}$

$\sf \:  ⟼ {r}^{2} = \dfrac{7 \: \: \cancel{175} \: \times 7}{2 \times \cancel{50} \: \: 2}$

$\sf \:  ⟼ {r}^{2} = \dfrac{7 \times 7}{2 \times 2}$

$\bf\implies \:r = \dfrac{7}{2} \: cm$

$\large{\boxed{\boxed{\bf{Hence, diameter \: = 7 \: cm}}}}$

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