Question

The volume of a cone is 462 m3. the height is 9. what is the radius

Answer 1

Given

The volume of a cone is 462 m3. the height is 9m

m. what is the radius

To find

Find the radius of cone

Solution

Height of cone = 9m

Volume of cone = 462m³

Applying formula → volume of cone

=> 1/3πr²h = 462

=> 1/3 × 22/7 × r² × 9 = 462

=> 22×9×r²/21 = 462

=> 198r²/21 = 462

=> r² = 21 × 462/198

=> r² = 9702/198

=> r² = 49

=> r = √49 = 7m

Hence, required height of cone is 7m

Some Formulae

• Volume of cylinder = πr²h
• Volume of cube = a³
• Volume of cuboid = l × b ×h
• Volume of cone = 1/3πr²h

Answer 2

$\sf \ Given :$

• The volume of a cone is 462 m³.

• Height of cone is 9 m.

$\sf \ To \: Find \: Out :$

Find the radius of cone?

$\sf \:Formula \: Used :$

$\boxed { \bigstar Volume \: of \: cone = \frac{1}{3} \pi {r}^{2} h}$

$\sf \: Solution:$

Let the radius of the cone be r m.

$\sf \: Volume \: of \: cone= \frac{1}{3}\pi {r}^{2} h$

$\bf \: Substituting \: the \: values </p><p></p><p> </p><p>$

$: \implies \: 462 = \frac{1}{ \cancel3} \times \frac{22}{7} \times {r}^{2} \times \cancel9$

$: \implies \: 462 = \frac{22}{7} \times {r}^{2} \times 3$

$: \implies \: 462 \times 7 = 66 \times {r}^{2}$

$: \implies \: 3234 = 66 \times {r}^{2}$

$: \implies \: {r}^{2} = \frac{3234}{66}$

$: \implies \: {r}^{2} = 49$

$: \implies \: r = \sqrt{49}$

$\therefore \: r = 7m$

Hence, The radius of given cone is 7 m.