Question

The volume of a cone with radius 6 cm and height equal to half of its radius is​

Answer 1

Answer:

$113\frac{1}{7}cm^{3}$

Step-by-step explanation:

Volume = $\frac{\pi r^{2}h}{3}=\frac{22}{7}*6*6*\frac{6}{2}*\frac{1}{3}=\frac{22}{7}*36=\frac{792}{7}=113\frac{1}{7}cm^{3}$

Hence proved.

Thank you.

Plzzz mark my answer as brainliest.

Answer 2

Given:

• Radius of cone = 6cm
• Height of cone = half of radius = $\sf \dfrac{r}{2} = \dfrac{6}{2} = 3cm$

Find:

• Volume of cone = ?

Solution:

we, know that

$\underline{\boxed{\sf \leadsto Volume \:of \: cone = \dfrac{1}{3} \pi {r}^{2} h}}$

where,

• π = $\sf \dfrac{22}{7}$
• r = 6cm
• h = 3cm

Substitute these values in the formula

$\sf \mapsto Volume \:of \: cone = \dfrac{1}{3} \pi {r}^{2} h$

$\sf \mapsto Volume \:of \: cone = \dfrac{1}{3} \times \dfrac{22}{7} \times {(6)}^{2} \times (3)$

$\sf \mapsto Volume \:of \: cone = \dfrac{1}{3} \times \dfrac{22}{7} \times 36 \times 3$

$\sf \mapsto Volume \:of \: cone = \dfrac{22}{21} \times 108$

$\sf \mapsto Volume \:of \: cone = \dfrac{2376}{21} = 113.142$

$\underline{\boxed{\sf \longrightarrow Volume \:of \: cone = 113.1 {cm}^{3}}}$

$\rule{81}{4}$

Hence, the volume of the cone will be 113.1cm³