The volume of a conical tent is 1232 cu. m and the area of its base is 154 sq. m. find the length of the canvas required to build the tent, if the canvas is 2m in width. (take π = 22/7)
Answers
Answered by
1
the length is 11root 113 m.
hope it helps. . . . . mark as brainliest answer
hope it helps. . . . . mark as brainliest answer
Attachments:
Aryanmalewar:
mark as brainliest answer
Answered by
0
Hii friend,
AREA OF BASE OF CONICAL TENT = πR²
154 = 22/7×R²
R² = 154×7/22
R² = 49
R = ✓49 = 7CM
VOLUME OF CONICAL TENT = 1232 CM³
1/3πR²H = 1232
1/3×22/7×7×7 × H = 1232
H =24 M²
SLANT HEIGHT = UNDER ROOT (H)² + (R)² = (24)² + (7)² = 576 + 49 = ✓625 = 25 M
CANVAS REQUIRED TO MAKE THE TENT = CSA OF TENT = πRL
= 22/7×7×25
= 22×25 = 550 M²
Therefore,
AREA = LENGTH × BREADTH
550 = LENGTH × 2
LENGTH = 704/2 = 225 M
AREA OF BASE OF CONICAL TENT = πR²
154 = 22/7×R²
R² = 154×7/22
R² = 49
R = ✓49 = 7CM
VOLUME OF CONICAL TENT = 1232 CM³
1/3πR²H = 1232
1/3×22/7×7×7 × H = 1232
H =24 M²
SLANT HEIGHT = UNDER ROOT (H)² + (R)² = (24)² + (7)² = 576 + 49 = ✓625 = 25 M
CANVAS REQUIRED TO MAKE THE TENT = CSA OF TENT = πRL
= 22/7×7×25
= 22×25 = 550 M²
Therefore,
AREA = LENGTH × BREADTH
550 = LENGTH × 2
LENGTH = 704/2 = 225 M
Similar questions