The volume of a conical tent is 1232 cubic meter and the area of it base is 154 sq meter.if the breadth of the canvas is 2 meter,then how long canvas Will required for the tent ?
Answers
Answered by
166
Hello Mate!
Volume of conical tent = ⅓πr²h
Area of circular base = πr²
Area of circular base, πr² = 154 m²
1232 m³ = ⅓ × 154 m²
24 m = height
154 m² = πr²
154 m² × 7 / 22 = r²
49 = r² = 7
l = √( r² + h² )
= √( 7² + 24² )
= √625 = 25 cm
Curved surface area of cone = πrl
= 22/7 × 7 × 25 m² = 550 m²
So 550 m² canvas must be used,
Length × width = 550 m²
Length × 2 m = 550 m²
Length = 275 m
Have great future ahead!
Volume of conical tent = ⅓πr²h
Area of circular base = πr²
Area of circular base, πr² = 154 m²
1232 m³ = ⅓ × 154 m²
24 m = height
154 m² = πr²
154 m² × 7 / 22 = r²
49 = r² = 7
l = √( r² + h² )
= √( 7² + 24² )
= √625 = 25 cm
Curved surface area of cone = πrl
= 22/7 × 7 × 25 m² = 550 m²
So 550 m² canvas must be used,
Length × width = 550 m²
Length × 2 m = 550 m²
Length = 275 m
Have great future ahead!
Answered by
37
given a conical tent with
Volume of the tent = 1232 m3
nd area of the base = 154m2
Let its radius be r
Area of the base = TTr2
= 22/7 x r2 = 154m2
= r2 = 154 x 7/22
= r2 = 49
= r = 7m
now its height = TTr2h
= 22/7 x 7m x 7m x h = 1232m3
= 154h = 1232m3
= h = 8m
Now, its length = l2 = h2 + r2
= l2 = ( 8m )2 + ( 7m )2
= l2 = 64m + 49m
= l2 = 113
= l = 10.63 ( approx )...
Volume of the tent = 1232 m3
nd area of the base = 154m2
Let its radius be r
Area of the base = TTr2
= 22/7 x r2 = 154m2
= r2 = 154 x 7/22
= r2 = 49
= r = 7m
now its height = TTr2h
= 22/7 x 7m x 7m x h = 1232m3
= 154h = 1232m3
= h = 8m
Now, its length = l2 = h2 + r2
= l2 = ( 8m )2 + ( 7m )2
= l2 = 64m + 49m
= l2 = 113
= l = 10.63 ( approx )...
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