Question

The volume of a container is 0.9 m'. If it is 50 cm long and 120 cm wide, then find its depth.​

Answer 1

Solution:-

Given:

Volume of a container = 0.9 m³

Length of container = 50 cm

Widht of the container = 120 cm

To Find:

Depth of the container

Formula:

Volume = Length × Width × Depth

Firstly let us change the unit, so every unit will be same.

Volume = 0.9 m³

[ 1 m³ = 10,00,000 cm³ ]

= 9,00,000 cm³

So

Volume = Length × Width × Depth

⟹ 9,00,000 = 50 × 120 × Depth

⟹ 9,00,000 = 6,000 × Depth

⟹ 9,00,000/6,000 = Depth

⟹ 150 = Depth

⟹ Depth = 150 cm

Required Answer:-

Depth of the container = 150 cm

Or

Depth = 150 cm = 150/100 = 1.5 m [ 1 cm = 1/100 m ]

Answer 2

Question:

The volume of a container is 0.9 m'. If it is 50 cm long and 120 cm wide, then find its depth.

To find:

• Depth of the container

Given:

• Length of container = 50 cm

• Breadth of container = 120 cm

• Volume of container = 0.9 m³ = 900000 cm³

How?

we know:

1 m = 100cm

so:

$\leadsto \sf0.9 {m}^{3}$

$\leadsto \sf \dfrac{9}{10} {m}^{3}$

$\leadsto \sf \dfrac{9}{10} \times m \times m \times m$

$\leadsto \sf \dfrac{9}{10} \times 100 \times 100 \times 100$

$\leadsto \sf \dfrac{9}{1\cancel0} \times 100 \times 100 \times 10\cancel0$

$\leadsto \sf9 \times 100 \times 100 \times 10$

$\leadsto \sf900000 \: {cm}^{3}$

Let:

• Depth (height) = x

Now we know:

$\bigstar \boxed{ \rm Volume \: of \: cuboid=length \times breadth \times height }$

By using this formula we can find value of height

$\dashrightarrow\sf Volume \: of \: cuboid=length \times breadth \times height$

$\dashrightarrow\sf900000=x \times 50 \times 120$

$\dashrightarrow\sf \frac{900000}{50 \times 120} =x$

$\dashrightarrow\sf x = \frac{900000}{50 \times 120}$

$\dashrightarrow\sf x = \frac{9000\cancel0\cancel0}{5\cancel0 \times 12\cancel0}$

$\dashrightarrow\sf x = \frac{9000}{5 \times 12}$

$\dashrightarrow\sf x = \frac{9000}{60}$

$\dashrightarrow\sf x = \cancel {\frac{9000}{60}}$

$\dashrightarrow \underline{\boxed{\sf x =150\:cm}}$

$\therefore \underline{\sf Depth ~of~container~=150\:cm}$