Question

The volume of a cube is a perfect square. If the side length of the cube is a single digit integer, what will the maximum surface area of the cube (in m 2 )

Answer 1

Answer:

The correct answer is side=4 m

The maximum surface area is 96 m 2

Answer 2

Step-by-step explanation:

• According to the question the volume of a cube is a perfect square
• So let m be the side of a cube.
• So volume of cube will be m^3.
• Let n be any positive integer and so we get
•            So m^3 = n^2 (since cube is equal to perfect square)
•  Given side length of the cube is a single digit integer (that is 1 to 9)
• So if m = 9
•            So n^2 = 9^3
•           Or n^2 = 729
•          Or n = 27
• Now the single digit integer will be 9 since the condition is satisfied.
• So total surface area of the cube is 6a^2
•                                                      So 6 x 9^2
•                                                         6 x 81
•                                                       486 sq m  

Reference link will be

https://brainly.in/question/40787047