the volume of a cube is increased by 700% by how much will its surface area increase
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Step-by-step explanation:
Given the volume of a cube is increased by 700% by how much will its surface area increase
- So the volume of a sphere is V = 4/3 πr^3
- We have Surface area of sphere S = 4 πr^2
- Given volume of a cube is increased by 700%
- So Volume V1 and V2 will be the initial and final volume.
- Therefore V2 / V1 = 8
- Or 4/3 πr2^3 / 4/3 πr1^3 = 8
- Or r2^3 / r1^3 = 8
- So (r2 / r1)^3 = 2^3
- Or r2 / r1 = 2
- Similarly S2/S1 = 4πr2^2 / 4 π r1^2
- = (r2 / r1)^2
- = (2)^2
- = 4
- Therefore S2 = 4 S1
- Or S2 – S1 = 3 S1
- = 300 %
- Therefore the increase in surface area is 300%
Reference link will be
https://brainly.in/question/23318726
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