The volume of a cube is increasing at the rate of 9 cm^3/sec. How fast is the surface area increasing when the length of an edge is 10 cm.
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V1 = 1000cm³
V2 = 1009cm³
Old side = 10cm
New edge = √1009 = 10.02cm
S1 = 6×10²
S1 = 600cm²
S2 = 6×(10.02)²
S2 = 602.40 cm²
Increase = 602.40 - 600/600 × 100
Increase = 0.4%
V2 = 1009cm³
Old side = 10cm
New edge = √1009 = 10.02cm
S1 = 6×10²
S1 = 600cm²
S2 = 6×(10.02)²
S2 = 602.40 cm²
Increase = 602.40 - 600/600 × 100
Increase = 0.4%
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