The volume of a cube is x^3 + 3x^2 +3x + k. If its length is x +1, find k
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Answered by
16
Answer:
GIVEN , X + 1 = 0
==> X= -1
GIVEN ==> X³+3X²+3X+K
PUUTING VALUE OF X IN EQ(1)
==> (-1)³ + 3(-1)² + 3(-1) + K
==> -1 + 3 -3 +K
==> -1+K =0
==> K = 1
Answered by
6
hi dude
h r u
your answer is here
x+1=0
x^3+3x^2+3x+k
(-1)^3+3(-1)^2+3(-1)+k
-1+3-3+k
-1+k=0
k=1
Thank you
h r u
your answer is here
x+1=0
x^3+3x^2+3x+k
(-1)^3+3(-1)^2+3(-1)+k
-1+3-3+k
-1+k=0
k=1
Thank you
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