Question

The volume of a cube with side -0.5/7x^2y is __________.

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Answer 1

Step-by-step explanation:

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Answer 2

Given: side of the cube$=\[{ - \frac{{0.5}}{{7{x^{2y}}}}}\]$.

Solution:

Find the volume of the cube.

Volume of the cube$=(side)^{3}$

                                 $\[ = \left( { - \frac{{0.5}}{{7{x^{2y}}}}} \right) \times \left( { - \frac{{0.5}}{{7{x^{2y}}}}} \right) \times \left( { - \frac{{0.5}}{{7{x^{2y}}}}} \right)\]$

                                 $\[ = - \frac{{0.125}}{{343{x^{2y + 2y + 2y}}}}\]$

                                 $\[ = - \frac{{0.125}}{{343{x^{6y}}}}\]$

Hence, the colume of the cube with side$\[{ - \frac{{0.5}}{{7{x^{2y}}}}}\]$ is $\[ - \frac{{0.125}}{{343{x^{6y}}}}\]$.