Question

the volume of a cubical box is 4096m³. find the length of each side of the box​

Answer 1

Answer:

side of the box = 16 m

Step-by-step explanation:

hope it helps you

Answer 2

Given : The volume of a cubical box is 4096m³.

Need To Find: The Length of each side of box .

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❍ Let's Consider the a Length of the Side of the cubical box.

$\dag\frak{\underline {As,\:We\:know\:that,\:}}$

$\star\boxed {\pink{\sf{ Volume_{(Cube)}= a \times a \times a \:or\:a^{3} \:cu.units}}}$

Where,

• a is the Length of the Side of the Cubical box .

⠀⠀⠀⠀⠀⠀$\underline {\bf{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$\qquad \quad :\implies \sf { a^{3} = 4096 }$

$\qquad \quad :\implies \sf { a = \sqrt [3]{4096} }$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm {  a = 16\: m}}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {  Hence \:The\:Length \:of\:side\:of\:Cubical \:box\:\:is\:\bf{16\: m}}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

⠀⠀⠀⠀⠀⠀⠀⠀$\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

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