Question

the volume of a cuboid is 3600 cm cube and its height is 12 CM the cross section is a rectangle whose length and breadth are in the ratio 4 ratio 3 find the perimeter of the cross section

Answer 1

let l =4x
   B=3x 
  h =12cm
 V = L×B×H=3600
  or 4x ×3x ×12 =3600
    12x²×12 =3600
  x² = 3600 \12×12
  or  x² =300\12
 or    x² =100\4 =25
or x = 5
then L =4×5=20 and B=3×5=15
L=20  B =15 ans.

Answer 2

Perimeter of the cross section is 70 cm

Step-by-step explanation:

Length : Breadth = 4:3

Let the ratio be x

Length = 4x

Breadth = 3x

Height of cuboid = 12 cm

Volume of cuboid  = $Length \times Breadth \times Height$

Volume of cuboid  = $4x \times 3x \times 12$

We are given that the volume of a cuboid is 3600 cm cube

So,  $4x \times 3x \times 12=3600$

$144x^2=3600$

$x^2=\frac{3600}{144}$

$x=\sqrt{\frac{3600}{144}}$

$x=5$

Length = 4x = 4(5) = 20 cm

Breadth = 3x=3(5)=15 cm

Cross section of cuboid is rectangle

Perimeter of rectangle = $2(l+b)=2(20+15)=70 cm$

Perimeter of the cross section is 70 cm

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