Question

The volume of a cuboid is 3x^2 -27 ,then its possible dimensions are (2 Points)

Answer 1

Answer:

infinite solutions (see explanation)

Step-by-step explanation:

given volume of cuboid = 3x²-27

lbh = 3x²-27

3x² = lbh+27

x² = (lbh+27)/3

x = √[ (lbh+27)/3]

x = √(lbh/3) + 27/3

x = √(lbh/3) + 9

some details are missing in the question, and hence we can assume any suitable value for l,b,h to make x , a natural number greater than 9 ( square root of any number cannot be negative unless it is imaginary)

eg, if i take x =  10,

then √(lbh/3) = 1

ie, lbh/3 = 1² = 1

=> lbh = 1 x 3 = 3units

so, we can assume l = 3 units, b = 1 unit  and h = 1 unit

and so on........................

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