Question

The volume of a cuboid shaped tank is 3600 cm3 . Its height, breadth and length are three consecutive perfect squares. Find its length, breadth and height. (Write 3600 as a product of prime factors).

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Perimeter of the cross section is 70 cm

Step-by-step explanation:

Length : Breadth = 4:3

Let the ratio be x

Length = 4x

Breadth = 3x

Height of cuboid = 12 cm

Volume of cuboid = Length \times Breadth \times HeightLength×Breadth×Height

Volume of cuboid = 4x \times 3x \times 124x×3x×12

We are given that the volume of a cuboid is 3600 cm cube

So, 4x \times 3x \times 12=36004x×3x×12=3600

144x^2=3600144x

2

=3600

x^2=\frac{3600}{144}x

2

=

144

3600

x=\sqrt{\frac{3600}{144}}x=

144

3600

x=5x=5

Length = 4x = 4(5) = 20 cm

Breadth = 3x=3(5)=15 cm

Cross section of cuboid is rectangle

Perimeter of rectangle = 2(l+b)=2(20+15)=70 cm2(l+b)=2(20+15)=70cm

Perimeter of the cross section is 70 cm