Question

the volume of a cylinder is 300m³ then the volume of a cone having the same radius and height as that of the cylinder is​

Answer 1

Answer:

100 m³

Step-by-step explanation:

Volume of cylinder = πr²h

Given that 300m³

so πr²h = 300

Since height of cone and cylinder and radius of cone and cylinder are equal . so

volume of cone is 1/3(πr²h)

so volume of cone = 1/3 × 300 m ³

= 100 m³

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Answer 2

$\large\underline{\sf{Solution-}}$

Let assume that

• Radius of cylinder be 'r' m.

• Height of cylinder be 'h' m.

We know,

$\boxed{ \bf{ \: Volume_{cylinder)} \: = \: \pi \: {r}^{2} \: h}}$

Given that,

$\rm :\longmapsto\:Volume_{cylinder)} = 300$

$\red{\rm :\longmapsto\: \: \pi \: {r}^{2} \: h = 300 - - - (1)}$

Now,

Dimensions of cone

It is given that Dimensions of cone is same as that of cylinder.

So,

• Radius of cone = r m

• Height of cone = h m

We know,

$\rm :\longmapsto\:{ \bf{ \: Volume_{cone)} \: = \dfrac{1}{3} \: \pi \: {r}^{2} \: h}}$

On substituting the value from equation (1), we get

$\rm :\longmapsto\:{ \bf{ \: Volume_{cone)} \: = \dfrac{1}{3} \times 300}}$

$\rm :\longmapsto\:{ \bf{ \: Volume_{cone)} \: =100 \: {m}^{3} }}$

More information :-

Volume of cylinder = πr²h

T.S.A of cylinder = 2πrh + 2πr²

Volume of cone = ⅓ πr²h

C.S.A of cone = πrl

T.S.A of cone = πrl + πr²

Volume of cuboid = l × b × h

C.S.A of cuboid = 2(l + b)h

T.S.A of cuboid = 2(lb + bh + lh)

C.S.A of cube = 4a²

T.S.A of cube = 6a²

Volume of cube = a³

Volume of sphere = 4/3πr³

Surface area of sphere = 4πr²

Volume of hemisphere = ⅔ πr³

C.S.A of hemisphere = 2πr²

T.S.A of hemisphere = 3πr²