Question

the volume of a cylinder is 38500cm^3 .If the height of the cylinder is 40cm find the diameter of its base​

Answer 1

Answer:

Given :-

The volume of cylinder is 38500cm^3.If the height of the cylinder is 40cm.

♧To find :-

Here we should find diameter of the base.

♧Explanation :-

$volume \: of \: cylinder = {38500cm}^{3}$

$height \: of \: cylinder = 40cm$

$volume = \pi \: {r}^{2} h$

Now applying all the values we get that,

$volume = \frac{22}{7} \times {r }^{2} \times 40 = 38500$

$125.71 \times {r}^{2} = 38500$

${r}^{2} = \frac{38500}{125.71}$

${r}^{2} = 306.26 = \sqrt{306.26 } = 17.5$

$radius = 17.5cm$

$diameter = 2 \times r = 2 \times 17.5 = 35cm$

♧Therefore,

The diameter of the base is 35cm.

♧Hope it helps u mate .

♧Thank you .

$\huge\mathtt\red{\textsf{MrUniqueBoi}}$

Answer 2

Answer:

Given :-

The volume of cylinder is 38500cm^3.If the height of the cylinder is 40cm.

♧To find :-

Here we should find diameter of the base.

♧Explanation :-

volume \: of \: cylinder = {38500cm}^{3}volumeofcylinder=38500cm

3

height \: of \: cylinder = 40cmheightofcylinder=40cm

volume = \pi \: {r}^{2} hvolume=πr

2

h

Now applying all the values we get that,

volume = \frac{22}{7} \times {r }^{2} \times 40 = 38500volume=

7

22

×r

2

×40=38500

125.71 \times {r}^{2} = 38500125.71×r

2

=38500

{r}^{2} = \frac{38500}{125.71}r

2

=

125.71

38500

{r}^{2} = 306.26 = \sqrt{306.26 } = 17.5r

2

=306.26=

306.26

=17.5

radius = 17.5cmradius=17.5cm

diameter = 2 \times r = 2 \times 17.5 = 35cmdiameter=2×r=2×17.5=35cm

♧Therefore,

The diameter of the base is 35cm.

♧Hope it helps u mate .

♧Thank you .

\huge\mathtt\red{\textsf{MrUniqueBoi}}