THE VOLUME OF A CYLINDER IS 48.125cm cube , WHICH IS FORMED BY ROLLING A RECTANGULAR PAPER SHEET ALONG THE LENTH OF THE PAPER . IF A CUBOIDAL BOX ( WITHOUT ANY LID i.e , OPEN AT THE TOP ) IS MADE FROM THE SAME SHEET OF PAPER BY CUTTING OUT THE SQURE OF SIDE 0.5 cm FROM EACH OF THE FOUR CORNERS OF PAPER SHEET, THEN WHAT IS THE VOLUME OF THE BOX ?
A ) 20cm CUBE
B ) 38 cm CUBE
C ) 19 cm CUBE
D ) 28 cm CUBE
Answers
Answered by
23
# Answer- 20cu.cm.
# Solution-
Let's consider
Volume of cylinder=πbr^2=48.125
br^2=15.3125
Assuming r^2 has perfect square
b=5 and r=1.75
Now, rectangular sheet has length of 2πr=11cm and width b=5cm.
After cutting a square of 0.5cm from each corner, the dimension of the cuboid becomes:
Length=11-1=10cm;
Breadth=5-1=4cm;
Height=0.5cm.
Therefore,
Volume of cuboid= 10x4x0.5 = 20cm^3.
# Solution-
Let's consider
Volume of cylinder=πbr^2=48.125
br^2=15.3125
Assuming r^2 has perfect square
b=5 and r=1.75
Now, rectangular sheet has length of 2πr=11cm and width b=5cm.
After cutting a square of 0.5cm from each corner, the dimension of the cuboid becomes:
Length=11-1=10cm;
Breadth=5-1=4cm;
Height=0.5cm.
Therefore,
Volume of cuboid= 10x4x0.5 = 20cm^3.
Answered by
5
Answer:
20cm3 option a is correct
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