Math, asked by IamSumanhii, 2 months ago

the volume of a cylinder is 6600cmcube.what will be its height it its circular base has a radius of 10cm.

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Answers

Answered by IamSameerhii
39

Given -

  • Volume of cylinder = 6600cm³
  • Base radius of cylinder = 10 cm

To find -

  • Height of the Cylinder

Formula used -

  • Volume of cylinder = πr²h

Solution -

  • In the question, we are provided with the volume and the base radius of a cylinder, and we need tk find it's height, for that we will use the formula of volume of cylinder, and will put the given values, and then we will do the further the question.

According to question -

  • Base radius = 10 cm

  • Volume = 6600 cm³

  • Height = h

  • Volume of cylinder = πr²h

Where -

π = \sf\dfrac{22}{7}

  • r = Radius

  • h = Height

On substituting the values -

\sf \longrightarrow \: volume \: = \pi \: {r}^{2}h \\ \\ \\ \sf \longrightarrow \: 6600 {cm}^{3} \: = \dfrac{22}{7} \times {(10 \: cm)}^{2} \times h \\ \\ \\ \sf \longrightarrow \: 6600 {cm}^{3} \: = \dfrac{22}{7} \: \times \: 100 \: cm \: \times \: h \\ \\ \\ \sf \longrightarrow 6600 {cm}^{3} \: = \dfrac{2200}{7} \: \times \: h \\ \\ \\ \sf \longrightarrow \: 6600{cm}^{3} = \: 314.28 \: \times \: h \\ \\ \\ \sf \longrightarrow \: h \: = \dfrac{6600}{314.28} \\ \\ \\ \sf \longrightarrow \: h \: = 21cm \: \: (approx) \\ \\

\boldsymbol {\therefore The \:height\: of\: the\: given \:Cylinder\: is \:21cm (approx)}

____________________________________

Answered by IamSameerhii1
3

Given -

  • Volume of cylinder = 6600cm³
  • Base radius of cylinder = 10 cm

To find -

  • Height of the Cylinder

Formula used -

  • Volume of cylinder = πr²h

Solution -

  • In the question, we are provided with the volume and the base radius of a cylinder, and we need tk find it's height, for that we will use the formula of volume of cylinder, and will put the given values, and then we will do the further the question.

According to question -

  • Base radius = 10 cm
  • Volume = 6600 cm³
  • Height = h
  • Volume of cylinder = πr²h

Where -

π = \sf\dfrac{22}{7}

  • r = Radius
  • h = Height

On substituting the values -

\sf \longrightarrow \: volume \: = \pi \: {r}^{2}h \\ \\ \\ \sf \longrightarrow \: 6600 {cm}^{3} \: = \dfrac{22}{7} \times {(10 \: cm)}^{2} \times h \\ \\ \\ \sf \longrightarrow \: 6600 {cm}^{3} \: = \dfrac{22}{7} \: \times \: 100 \: cm \: \times \: h \\ \\ \\ \sf \longrightarrow 6600 {cm}^{3} \: = \dfrac{2200}{7} \: \times \: h \\ \\ \\ \sf \longrightarrow \: 6600{cm}^{3} = \: 314.28 \: \times \: h \\ \\ \\ \sf \longrightarrow \: h \: = \dfrac{6600}{314.28} \\ \\ \\ \sf \longrightarrow \: h \: = 21cm \: \: (approx) \\ \\

\boldsymbol {\therefore {The \:height\: of\: the\: given \:Cylinder\: is \:21cm (approx)}}

____________________________________

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