Math, asked by geethika12314, 1 year ago


The volume of a cylindrical bottle of radius 2 cm is 88 cm^3then its height is

Answers

Answered by ButterFliee
31

Answer:

Hello

Step-by-step explanation:

ATQ

πr^2h = 88

22/7*2*2*h = 88

h = 88*7/22*4

h = 7cm

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Answered by Anonymous
17

\Large\underline{\underline{\sf \orange{Given}:}}

  • Radius of bottle (R) = 2cm

  • Volume of bottle (V) = 88cm³

\Large\underline{\underline{\sf \orange{To\:Find}:}}

  • Height of bottle (h) = ?

\Large\underline{\underline{\sf \orange{Formula\:Used}:}}

{\boxed{\sf \red{Volume\:of\: Bottle (V)=πR^2h}}}

\Large\underline{\underline{\sf \orange{Solution}:}}

\implies{\sf 88=\dfrac{22}{7}×(2)^2×h}

\implies{\sf 88=\dfrac{22}{7}×4×h}

\implies{\sf h=\dfrac{88×7}{22×4} }

\implies{\sf h=\dfrac{616}{88} }

\implies{\sf h=7\:cm }

\Large\underline{\underline{\sf \orange{Answer}:}}

{\sf \blue{\therefore Height\:of\: cylinderical\:bottle\:is\:7cm}}

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