Math, asked by Anonymous, 5 months ago

the volume of a cylindrical of the is 150 pie cm³. and its height is 6 cm . Find the areas of its total surface and lateral curved surface ?.​

Answers

Answered by Anonymous
1

Question:

the volume of a cylindrical of the is 150 pie cm³. and its height is 6 cm . Find the areas of its total surface and lateral curved surface

Answer:

\star\:\:\:\bf\large\underline\red{Given}

the volume of a cylindrical of the is 150 pie cm³.

its height is 6 cm

\star\:\:\:\bf\large\underline\red{To\:find}

Find the areas of its total surface and lateral curved surface

\star\:\:\:\bf\large\underline\red{Solution}

Volume of cylinder = 150π cm³

As wwe know that volume of the cylinder is given as-

\boxed{\bf{\blue{V=πr^{2}h}}}

Where,

V = Volume of the cylinder

r = Radius of the cylinder

h = height of the cylinder

ATQ,

\sf{\implies πr^{2}h=150}

\sf{\implies r^{2}=\dfrac{150}{6}}

\sf{\implies r=\sqrt{25}}

\sf{\implies r=5}

We also know that,

\boxed{\bf{\green{Lateral\:surface\:area\:of\:cylinder=2πrh}}}

.°. Lateral surface area of the cylinder

= 2πrh

= 2 × π × 5 × 6 cm²

= 60 π cm²

Now,

\boxed{\bf{\purple{Total\:surface\:area\:of\:cylinder=2πr(r+h)}}}

Therefore,

Total surface area of the cylinder

= 2πr(r+h)

= 2 × π × 5 × (5 + 6) cm²

= 110π cm²

Therefore,

lateral curved surface of the cylinder is 60 cm² and

Total surface area of the cylinder is 110π cm²

______________________________

Answered by Anonymous
3

Question:

the volume of a cylindrical of the is 150 pie cm³. and its height is 6 cm . Find the areas of its total surface and lateral curved surface

Answer:

\star\:\:\:\bf\large\underline\red{Given}

the volume of a cylindrical of the is 150 pie cm³.

its height is 6 cm

\star\:\:\:\bf\large\underline\red{To\:find}

Find the areas of its total surface and lateral curved surface

\star\:\:\:\bf\large\underline\red{Solution}

Volume of cylinder = 150π cm³

As wwe know that volume of the cylinder is given as-

\boxed{\bf{\blue{V=πr^{2}h}}}

Where,

V = Volume of the cylinder

r = Radius of the cylinder

h = height of the cylinder

ATQ,

\sf{\implies πr^{2}h=150}

\sf{\implies r^{2}=\dfrac{150}{6}}

\sf{\implies r=\sqrt{25}}

\sf{\implies r=5}

We also know that,

\boxed{\bf{\green{Lateral\:surface\:area\:of\:cylinder=2πrh}}}

.°. Lateral surface area of the cylinder

= 2πrh

= 2 × π × 5 × 6 cm²

= 60 π cm²

Now,

\boxed{\bf{\purple{Total\:surface\:area\:of\:cylinder=2πr(r+h)}}}

Therefore,

Total surface area of the cylinder

= 2πr(r+h)

= 2 × π × 5 × (5 + 6) cm²

= 110π cm²

Therefore,

lateral curved surface of the cylinder is 60 cm² and

Total surface area of the cylinder is 110π cm²

______________________________

Similar questions