Question

The volume of a cylindrical rod is 628 cm cube .If its height is 20 cm , find the radius of its cross section . ( use pie = 3.14) .

Answer 1

2 x pie x r x r x 20= 628cm
2 x 3.14 x r x r x 20 = 628cm
  6.28 x 20 x r x r = 628cm
125.60 - 628 = r sq. 
554.40 = r sq. 
 therefore 2/ 554.40= 277.20
answer is 277.20 

Answer 2

The radius of its cross section is 3.16 cm.

• The capacity of a cylinder, which determines how much material it can carry, is determined by the cylinder's volume. There is a formula for the volume of a cylinder that is used in geometry to determine how much of any quantity, whether liquid or solid, may be immersed in it uniformly. A cylinder is a three-dimensional structure having two parallel, identical bases that are congruent.
• The amount of unit cubes (cubes of equal length) that can fit within a cylinder is its volume. It is the space the cylinder occupies, just as the space occupied by any three-dimensional object is its volume.

Here, according to the given information, we are given that,

The volume of a cylindrical rod is 628 cm³.

Height (h) = 20 cm.

Then, we know that,

Volume of a cylinder = $\pi r^{2} h$, where r is the radius of its cross section.

Then, we get,

$628 = (3.14).(20)r^{2}$

Or, r = $\sqrt{\frac{628}{62.8} } = 3.16$ cm.

Hence, the radius of its cross section is 3.16 cm.

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