the volume of a cylindrical vessel is 770cm. if its radius is 7 then find its height and area of the base
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Answered by
9
Answer:
Given,
Volume of cylindrical vessel=770 cm
Radius =7 cm
Hence, πr²h= 770
Or, h= 770/πr²
Or, h= 770*7/22*7*7
Or, h= 5 cm.
Hence area of base = πr²= 22/7*7*7=154 cm²
Answered by
3
Answer:
Given ratio = 2:3 and volume = 1617 cm^3.
Let the radius and height of the cylinder be 2x and 3x. --(1)
Given volume of cylinder = 1617 cm^3
pir^2h = 1617 cm^3
(22/7) " (2x)^2* 3x = 1617
22/7 4x^2 " 3x = 1617
x = 7/2
Substitute x = 7/x in (1), we get
radius = 2* 7/2 = 7
height = 3*7/2 = 21/2. =
T.S.A of the cylinder = 2pir(h+r)
= 222/ 77*(212+
= 22 35
= 770 cm^2.
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