Question

The volume of a fish tank is 30 cubic feet. if the density is 0.3fish over feet cubed, how many fish are in the tank?

Answer 1

The answer is 9 fish. The density (d) is the number of units(n) per volume (V): d = n/V We know: d = 0.3 fish/ft³. V = 30 ft³ n = ? d = n/V n = d * V n = 0.3 fish/ft³ * 30 ft³ n = 9 fish

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Answer 2

9 fishes are in the fish tank whose volume is 30 cubic feet.

Given:

Volume of the fish tank = $30$cubic feet  

Density of the fish = $0.3$ cubic feet  

To find:

Number of fishes in the tank = ?

Solution:

The volume of the fish tank is $30 \text { feet }^{3}$.

The density of the tank is equal to $0.3$ fish over cubic feet.

Now to calculate the number of fishes present in the tank is using the proportionality between the volume and density, which is $\bold{V=\frac{n}{d}}$.

The value n is given to the number of the fishes present in the tank.

Therefore, according to the formula  

$\begin{array}{l}{V=\frac{n}{d}} \\ {30=\frac{n}{0.3}} \\ {n=9}\end{array}$

The number of fishes in the tank is 9 fishes.