Question

the volume of a fixed mass of gas at 300K is 10L. What will be the volume of the gas , if the temperature is doubled without changing the pressure? ​

Answer 1

Explanation:

And if the temperature is doubled, the volume increases to twice the original volume. If both the changes take place simultaneously,.

Answer 2

Answer:

The volume of the fixed mass of gas kept at 300K and occupying 10L initially will become 20L if the temperature is doubled.

Explanation and Calculation:

This question can be solved with the help of Charle's Law.

What is Charle's Law and its statement?

Charle's law states that:

At constant pressure, the volume of a given amount of gas is directly proportional to the temperature of the system.

Mathematically, Charle's law can be represented as:

Volume ∝ Temperature

⇒ V ∝ T [when pressure (P) and mass (m) of the gas is constant]

⇒ $\frac{V}{T}$ = constant

⇒ $\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$ = constant

Now, according to the question,

The volume of the gas initially ($V_{1}$) = 10L

The temperature initially ($T_{1}$) = 300K

The final temperature = (2×300) K = 600K

The final volume of the gas= x (let)

∴ By the problem,

$\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

⇒ $\frac{10L }{300K } = \frac{x}{600K}$

⇒ $10L = \frac{x}{2}$

⇒ x = 20L

Conclusion:

The volume of the gas will become 20L if the temperature of the system is doubled.

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