The volume of a gas 4 ATM pressure and 273 kelvin temperature is 500 ml what will be volume it the pressure is decreases to 2 ATM?
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Considering the gas is ideal gas, hence gas law's will be applicable on it.
PV = nRT , where P is pressure, V is volume, n is number of moles, R is constant, T is temperature.
Through this formula, at constant temperature we get P1V1 = P2V2,
Here, P1 is 2, V1 is 10, P2 is (2+4= 6), V2 is unknown.
SO, 2*10 = 6*V2
20= 6V2
V2 = 20/6= 3.33
Hence, the volume of gas at constant temperature will be 3.33 L, if the pressure is increased by 4 ATM.
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