Question

The volume of a gas at 0 degree C and 760mm pressure is 22.4 cc . The no. of molecules present in this volume is

Answer 1

Answer: $59.6\times 10^{19}$ molecules.

Explanation:

According to the ideal gas equation:'

$PV=nRT$

Pressure of the gas = 760 mmHg= 1atm

Volume of the gas = $22.4ml$ = 0.0224L

Temperature of the gas = 0°C = 273 K(0°C = 273 K)

Value of gas constant in in kilopascals = 0.0821 atmL\K mol

$n=\frac{PV}{RT}=\frac{1atm\times 0.0224L}{0.0821 atmL/K mol\times 273 K}=9.9\times 10^{-4}mol$

According to Avogadro's law,

1 mole of every substance contains avogadro's number $6.023\times 10^{23}$ of particles.

Thus $9.9\times 10^{-4}mol$ moles of gas will contain=$\frac{6.023\times 10^{23}}{1}\times 9.9\times 10^{-4}=59.6\times 10^{19}$ molecules.

Answer 2

Answer is in the photo