the volume of a gas at 23°C temperature 752mm pressure and 0.324 gm of mass is 280cm³.what will be the molecular mass of the gas
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Answer:
volume=380 ml=0.380 liters
temperature= 27
0
c=273+27=300K
Now, using by formula
PV=nRT (R= gas constant= 8.2×10
2
n=
RT
pv
=
8.2×10
2
×300
1.052×0.380
=0.0162
Now, given mass of the gass is 0.455
no of moles=
molarmass
mass
molar mass=
noofmoles
mass
0.0162
0.455
=28.08g/mole
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