Question

the volume of a gas at 32° temperature 752mm pressure and 0.324 gm of mass is 280cm³.what will be the molecular mass of the gas​

Answer 1

Explanation:

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volume=380 ml=0.380 liters

temperature= 27

0

c=273+27=300K

Now, using by formula

PV=nRT (R= gas constant= 8.2×10

2

n=

RT

pv

=

8.2×10

2

×300

1.052×0.380

=0.0162

Now, given mass of the gass is 0.455

no of moles=

molarmass

mass

molar mass=

noofmoles

mass

0.0162

0.455

=28.08g/mole