The volume of a gas at STP is 273 ml. What will its volume be at a pressure of 38 cm of
mercury column a and a temperature of -23°C?
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Answer:
Explanation:
Solution :
Given,
V1=273 ml
P1=76 cm of Hg
T1=273 K
V2=?
P2=38 cm of Hg
T2=273−23=250 K
P1V1T1=P2V2T2
Substituting, we get 76×273273=38×V2250
V2=76×25038=2×250
V2=500 ml
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