Question

The volume of a gas expands by 0.25 m3 at a constant pressure of 10^3 N/m^2. The work done is equal to
(a) -250 watt
(b) -2.5 erg
(c) -250 newton
(d) -250 joule​

Answer 1

Answer :

• Work done = -250 J.

Step-by-step explanation:

Given that,

• Change in volume of gas, ΔV = 0.25 m³.
• Constant pressure, P= 10³ N/m².

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We know,

Work done, W = -PΔV

Putting the values, we get,

⇒ W = -10³ × 0.25 N m

⇒ W = -250 N m

⇒ W = -250 J (joule).

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[ NOTE : Here, work done by the system is negative. This indicates that the system has lost energy energy by performing work on its surroundings. This happens due to an increase in the volume at constant pressure.]