Question

The volume of a gas expands by 0.25m3 at a constant pressure of 10^3nm-2 the work done is equal to

Answer 1

First change m^3 to lit 1m^3=10^3lit ; 0.25m^3 = 250lit W=-P[V] (-ve due to expansion) Now change pressure from pascal to atm  10^3pa=0.0098atm W= -0.0098*250 atmlit W= -2.25atmlit (1atm lit =101.33J) W= -2.25*101.33 W= 250J

Answer 2

Answer:

250 J

Explanation:

Convert m^3 in to Litre

and convert 10^3Pascal into atmosphere

And apply w = - PV equation