Question

the volume of a given mass of a gas is 0.54 dm^3 at a pressure of 60kNm^-2. calculate the pressure required to make the volume 0.8dm^3,the temperature is constant​

Answer 1

Answer:

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Explanation:

The ideal gas equation relating pressure (P), volume (V), and absolute temperature (T) is given as:

PV = nRT

Where,

R is the universal gas constant =8.314Jmol

−1

K

−1

n = Number of moles = 1

T = Standard temperature = 273 K

P = Standard pressure = 1 atm =1.013×10

5

Nm

−2

∴V=nRT/P

=1×8.314×273/(1.013×10

5

)

=0.0224m

3

=22.4 litres

Hence, the molar volume of a gas at STP is 22.4 litres.

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Answer 2

Answer:

40.5 kNm^-2

Explanation:

Given:- P1=60kNm^-2, P2= ?, V1=0.54dm^3, V2=0.8dm^3

According to Boyle's Law-

P1V1=P2V2

60×0.54=P2×0.8

P2=60×0.54\0.8=40.5

Therefore, Pressure=P2=40.5kNm^-2

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