Question

The volume of a hall is 475 m3

. The area of wall is 200 m2

, area of floor and ceiling each is 100

m

2

. If absorption of the wall, ceiling and floor are 0.025, 0.02 and 0.55 respectively. Calculate

the reverberation time for the hall​

Answer 1

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Answer 2

Answer:

The reverberation time for the hall​ is 1.27 sec.

Explanation:

Given,

Volume of hall, V = 475 m³

Area of wall, a₁ = 200 m²

Area of floor, a₂ = 100 m²

Area of ceiling, a₃ = 100 m²

Absorption coefficient, s₁ = 0.025

Absorption coefficient, s₂ = 0.02

Absorption coefficient, s₃ = 0.55

Reverberation time, T, for the hall​ is calculated by using this equation:

T= 0.167V/ ∑as

$T= \frac{0.167 * 475}{200*0.025 + 100*0.02 + 100*0.55}$

$T = \frac{79.325}{62}$

T = 1.27 sec

RESULT:

The reverberation time for the hall​ is 1.27 sec.