the volume of a metallic cylindrical pipe is 748 cm cube its length is 14 cm and its external radius is 9 cm find its thickness
Answers
Answered by
3
let internal radius be r
then
π*(9)²*14-π*r²*14=748
or 9²-r²=748/π*14
or r²=81-(748/44)
or r²=81-17
or r²=64
or r=8
then thickness of pipe is =9-8=1cm....(ans)
then
π*(9)²*14-π*r²*14=748
or 9²-r²=748/π*14
or r²=81-(748/44)
or r²=81-17
or r²=64
or r=8
then thickness of pipe is =9-8=1cm....(ans)
princelumar:
outstanding bro
Answered by
4
given length (h)= 14 cm
according to question ,
volume of cylindrical pipe = 748 cm^3
πr^2 h = 748
r^2= 748 × 7 /22× 14
r^2 = 748 /44
r^2 = 17
r = 4.1 cm
since, external radius = 9 cm
then, thickness of pipe
= 9 - 4.1 = 4.8 cm = 5cm( approximate )
_______________________________
Your answer : thickness = 4.8 cm
_______________________________
according to question ,
volume of cylindrical pipe = 748 cm^3
πr^2 h = 748
r^2= 748 × 7 /22× 14
r^2 = 748 /44
r^2 = 17
r = 4.1 cm
since, external radius = 9 cm
then, thickness of pipe
= 9 - 4.1 = 4.8 cm = 5cm( approximate )
_______________________________
Your answer : thickness = 4.8 cm
_______________________________
Similar questions