the volume of a mettalic cylindrical pipe is 748cm³.its length is 14cm and its external radius is 9cm. find the thickness
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volume of cylinder = π x h x (R^2 - r^2) = 748
h = 14 cm
R = 9 cm
by putting the values in the equation we get,
22/7 x 14 x (9^2 - r^2) = 748
44 x (81 - r^2) = 748
81 - r^2 = 748 / 44 = 17
81 - 17 = r^2 ⇒ r^2 = 64
r = √64 = 8 cm
thickness = R - r = 9 - 8 = 1 cm
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