The volume of a pipe with internal and external diameter 14cm and 28cm and height 10cm is *
Answers
Answer:
Step-by-step explanation:
Given, thickness of iron =3cm
external diameter = 56cm
Length of tube = 182cm
We know,
volume of hollow cylinder = πh(R²−r²)
∴ internal diameter = external diameter−2×thickness of iron
= 56−2×3
= 56−6
= 50cm
=> Outer radius(R) = 56÷2 = 28cm
inner radius(r) = 50÷2 = 25cm
∴ Volume of hollow cylinder = πh(R²−r²)
= 3.14×182(28²−25²)
= 3.14×82×159
= 90865.32cm³
Step-by-step explanation:
formula = 22/7 ×10(R1^2 - r2^2)cm^3
=22/7 ×10(28^2 - 14^2)cm^3
= after simplifying
= 18,480 cm^3