Math, asked by ankitasriv990, 9 months ago

the volume of a rectangular block of stone is 10368 dm³. its dimension are in the ratio of 3:2:1. if its entire surface is polished at 2 paisa per dm³, then find the cost incurred to polish​

Answers

Answered by prasadzadokar01
12

Step-by-step explanation:

let L=3x,b=2x, h=x

so, 3x*2x*x=6x^3

10368/6=x^3

1728=x^3

x=12

L=36, b=24 h=12

tota area to paint internal surface =2(lb+bh+lh)

=2(36*12+24*12+36*24)

=2(432+264+864)

=2(1560)

=3120

cost to paint internal surface = 3120*2=6240paisa

Answered by mostlymeow
9

given:

Volume of cuboidal box= 10368dm^3

Ratio of dimensions= 3:2:1

Rate of polishing its entire surface =2 paisa per dm^2

to find:

(I) dimensions of the block

(ii) cost of polishing at the rate of 2paisa per dm^3

solution:

let the dimensions of the block be X

volume of cuboid= l*b*h

10368 = 3x * 2x * x

10368. = 6x^3

6x^3. = 10368

x^3. = 10368/6

x^3. = 1728

X= 12

therefore,

length=3*12

=36 dm

breadth=2*12

=24dm

height=1*12

=12dm

total surface area of cuboid= 2(l*b+b*h+h*l) = 2(36*24+24*12+12*36)

=2( 864+288+432)

=2*1584

=3168 dm^2

therefore,

cost of polishing its entire surface

= rate * total surface area

= 2 * 3168

= 6336 paise

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