The volume of a rectangular box whose area of three adjacent faces are 42 cm2, 30 cm2 and 35 cm2 is
Answers
Step-by-step explanation:
Let Length = l , breadth = b , and height = h
Area of 1st adjacent face = Length × Breadth
15 cm² = l × b -------------(1)
So,In this case length can be 1 or 15 or 5 or 3
breadth can be 1cm or 15cm or 5cm or 3cm
Area of 2nd adjacent face = Breadth × Height
20 cm² = b × h --------------(2)
In this case breadth could be 1cm or 20cm or 5cm or 4cm or 10cm or 2cm
In both the cases 5 is common for breadth.
So, breadth is 5 cm
Put breadth= 5 cm in (1) we get,
15cm² = l × 5cm
⇒ length = 15cm²/5cm = 3cm
and
Putting breadth = 5cm in (2) we get,
20cm² = 5cm × height
⇒ height= 20cm²/5cm = 4cm
So, Length = 3 cm
Breadth = 5 cm
Height = 4 cm
We know that volume of cuboid is Length×Breadth×Height
So, Volume of cuboid = 3cm×5cm×4cm =60cm³
Thank you!!!!Hope this helps!!!!