Math, asked by problem8141, 10 months ago

The volume of a rectangular box whose area of three adjacent faces are 42 cm2, 30 cm2 and 35 cm2 is

Answers

Answered by abhishek5736
1

Step-by-step explanation:

Let Length = l , breadth = b , and height = h

Area of 1st adjacent face = Length × Breadth

                             15 cm² = l × b                           -------------(1)

So,In this case length can be 1 or 15 or 5 or 3

     breadth can be 1cm or 15cm or 5cm or 3cm

Area of 2nd adjacent face = Breadth × Height

                              20 cm² = b × h                         --------------(2)

In this case breadth could be 1cm or 20cm or 5cm or 4cm or 10cm or 2cm

In both the cases 5 is common for breadth.

  So, breadth is 5 cm

                     Put breadth= 5 cm in (1) we get,

                                 15cm² = l × 5cm

                               ⇒ length = 15cm²/5cm = 3cm 

and 

                             Putting breadth = 5cm in (2) we get,

                           20cm² = 5cm × height

                        ⇒ height= 20cm²/5cm = 4cm 

So, Length   = 3 cm

       Breadth = 5 cm

       Height   = 4 cm

We know that volume of cuboid is Length×Breadth×Height

So, Volume of cuboid = 3cm×5cm×4cm =60cm³ 

                                  Thank you!!!!Hope this helps!!!!

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