Question

The volume of a rectangular tank is (12x^3 + 20x^2 – x – 6). If the length is (3x + 2) and height is (2x + 3), find the width of the tank​

Answer 1

Answer:

volume = 12x³+20x²-x-6

length = 3x+2

height = 2x+3

soln:

volume = l*b*h

12x³+20x²-x-6 = 3x+2*2x+3*b

divide volume by length and height using GCD method

we get 2x-1

answer is b or w = 2x-1

Answer 2

Given that , the volume of the rectangular tank is

12x^3 + 20x^2 – x – 6

since we know that vol. of rect. is l×w×h

therefore vol. = (3x+2)×(2x+3)×(w)

=6x^2 + 9x + 4x + 6.(w)

= 6x^2 + 13x + 6.(w)

But given vol. of tank is 12x^3 + 20x^2 – x – 6

therefore 12x^3 + 20x^2 – x – 6 = 6x^2 + 13x + 6.(w)

then solve it .

sorry this question is not able to solve in the phone .

I make the eq. just solve it