Question

The volume of a right circular cylinder whose height is 40 cm,and circumference of its base is 66 cm is.

Answer 1

Answer:13,847$cm^{2}$

Step-by-step explanation:

circumference = $\pi$*2*r

                        = 66cm$cm^{2}$

so, r = 66 / (3.14*2)

        = 10.5cm

Volume =$\pi$*$r^{2}$*h

             = 3.14*10.5*10.5*40

             =13,847$cm^{2}$

          or =1.3847$m^{2}$

Hope this is helpful enough!

Answer 2

The volume of cylinder is 2640 cubic cm

Step-by-step explanation:

Circumference = $2 \pi r$

We are given that circumference of its base is 66 cm

So,$2 \pi r = 66\\2 \times \frac{22}{7} \times r=66\\r=\frac{66 \times 7}{22 \times 2}\\r=10.5$

Height of cylinder is 40 cm

Volume of cylinder = $2 \pi r h = 2 \times \frac{22}{7} \times 10.5 \times 40=2640 cm^3$

Hence The volume of cylinder is 2640 cubic cm

#Learn more:

Find the ratio of volume of cylinder. When the radius is halved, and the height is same to that of volume of cylinder.

https://brainly.in/question/9227543