Question

The volume of a sample of gas measured at 27 C is 10.0dm3
. What is the temperature
when the volume is reduced to 9.0dm3
at the same pressure?

Answer 1

Answer:

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Explanation:

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Answer 2

$\\ V_{1} = 10 dm^{3} = 10 Litre$

$\\T_{1} = 27\textdegree C= 300 K$

$\\ V_{2} = 9 dm^{3} = 9 Litre$

$\\ T_{2} = ?$

According to the 'CHARLES's LAW',

the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature if the pressure remains constant.

So,$\\ V\propto T$

 $\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

$\frac{10}{300} = \frac{9}{T_{2} }$

$\\ T_{2} = 270 K = 3 \textdegree C$

Hence, the temperature of the volume of gas at 9 dm³ is 270 K or 3⁰.