The volume of a sample of hydrogen gas was decreased from to at constant temperature. If the final pressure exerted by the hydrogen gas sample was what pressure did the hydrogen gas exert before its volume was decreased?
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Explanation:
satisfy the Boyle's law, which states that
P
⋅
V
=
a constant
when temperature is held constant. [1]
In other words, the pressure the gas exerts is inversely related to the volume of the airtight container.
Therefore
P
1
⋅
V
1
=
P
2
⋅
V
2
P
1
=
P
2
⋅
V
2
V
1
=
P
2
⋅
V
2
V
1
Evaluate with
V
1
=
13.16
L
,
V
2
=
6.45
L
,
P
2
=
7.73
atm
as given in the question:
P
1
=
7.73
atm
⋅
6.45
L
13.16
L
=
3.79
atm
(rounded to three significant
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