Question

the volume of a sphere is 4581 how much should it's radius be reduced that it's volume becomes 4312/3cm^3​

Answer 1

Given :- Volume of the sphere = 4851 cm³

⇒ 4/3πr³ = 4851

⇒r³ = 4851*3*7/4*22

⇒ r³ = 441*21/8

⇒r = ∛ 21*21*21 / 2*2*2

⇒ r = 21/2

⇒ r = 10.5 cm.

According question :-

Volume reduced in the sphere = 4312/3 cm³ .

⇒ 4/3 π r³ = 4312/3

⇒ r³ = 4312*3*7 / 3*4*22

⇒ r³ = 196*7/4  

⇒r³ = 49*7

⇒ r = ∛ 7*7*7

⇒ r = 7 cm.

Radius reduction is 10.5 cm - 7 cm.

⇒ 3.5 cm

∴ The radius should be reduced 3.5 cm

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