Question

The volume of an air bubble becomes six times as it Rises from the bottom of a lake to its surface assuming atmospheric pressure to be 75 cm of Mercury and density of water to be one tenth of the density of Mercury the depth of the lake is

Answer 1

Answer:3.75m

Explanation:

It is difficult to explain like this

From Boyle's law product of pressure and volume at the bottom is equal to the pressure and volume

Solving the equation can give the answer

Answer 2

We can assume that the process is isothermal because the temperature of the surrounding remains constant

So, by applying Boyle’s law

Ps Vs= Pd Vd......(1)

Where, s = surface of water

d=depth

Given that,

Depth of lake =h

Volume Vs= 3Vd

Now,

Ps=75 cmHG

$pd = 75 + \frac{h}{10}$

Now, put the value of equation(l)

$75 \times 3 = 75 + \frac{h}{10} \\ 225 - 75 = \frac{h}{10}$

h=1500cm

h=15m

Hence, the depth of lake is 15 m