the volume of certain mass of a gas is 0.6dm^3 at a pressure of 95.76kNm^-2.calculate the volume of the gas if the pressure is changed to 147.88kNm^-2 at the same temperature
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Explanation:
Given,
Initial volume =V
1
=0.6dm
3
Initial pressure =P
1
=101.325kPa
Final pressure P
2
=142.860kPa
Temperature is constant
We have to find V
2
At constant temperature by Boyle's law,
P
1
V
1
=P
2
V
2
⟹V
2
=
P
2
P
1
V
1
On substituting values we get,
V
2
=0.426dm
3
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