the volume of CO2 evolved at stp on heating 20 g of CaCo3
Answers
Answered by
2
Explanation:
100g = 1 mol
20g = 1/5 mol
1mol = 22.4 litter
1/5 mol = 22.4 * 1/5
= 4.48 litter
Answered by
1
Answer:
The volume of evolved at STP on heating 20g. of is found to be 4.48 L
Explanation:
Before solving the question, let us write down the data given:
- Weight of = 20g.
- The volume of 1 mol. of gas at STP= 22.4 L
To be calculated, the volume of evolved at STP on heating 20g. of .
As we know that 1 mol.= 100g.
That means 100g.= 1 mol.
20g.= × = 1/5 mol.
- As per the question, 1 mol. of gas at STP= 22.4 L
Hence to be calculated 1/5 mol. of gas= ?
- Let 1/5 mol. of gas= x
- So solving the above two equations we get,
x= ×
x= 4.48 L.
∴ x=4.48 L.
Hence the volume of evolved at STP on heating 20g. of .
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