the volume of co2 produced at Stp when 0.5moles of h2so4 reacts with 0.5moles of na2co3
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3
H2SO4 + Na2CO3 ➡ Na2SO4 + H2O + CO2
So , 1 mole each of H2SO4 and Na2CO3 gives 1 mole of CO2
So, 0.5mole of each will give 0.5 mole of CO2
We know , volume of 1 mole of a gas at STP is 22.4L
So , volume of 0.5 mole of CO2 produced at STP is 22.4/2 = 11.2 L
So , 1 mole each of H2SO4 and Na2CO3 gives 1 mole of CO2
So, 0.5mole of each will give 0.5 mole of CO2
We know , volume of 1 mole of a gas at STP is 22.4L
So , volume of 0.5 mole of CO2 produced at STP is 22.4/2 = 11.2 L
Answered by
1
the answer is 11.2.
b/c 1 mole na2co3 gives 1 mole co2 when react with 1 mole h2so4. and 1 mole gives 22. 4 L
so, half mole Wil give us 11. 2.
b/c 1 mole na2co3 gives 1 mole co2 when react with 1 mole h2so4. and 1 mole gives 22. 4 L
so, half mole Wil give us 11. 2.
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