Question

the volume of CO2 produced by heating 33.5 gram lithium carbonate (LI2CO3) at room temperature and pressure is​

Answer 1

Answer:

Explanation:

We follow the stoichiometric equation...

Li2O(s)+CO2(g)→Li2CO3(g)

There is thus 1:1 equivalence between the carbon dioxide and the lithium carbonate.

Moles of carbon dioxide=88⋅g44.0⋅g⋅mol−1=2⋅mol.

And thus a mass with respect to lithium carbonate of...

2⋅mol×73.89⋅g⋅mol−1=147.8⋅g...